[Codility] [5] PassingCars (score 100%)

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【Lesson 5】: PassingCars 計算向東的車(=0),向西的車(=1),計算車輛交會時的組合數量 (score 100%)

public static int PassingCars(int[] A){int S = 0;int count = 0;for (int i = 0; i < A.Length; i++){if (A[i] == 0)S++;elsecount += S;}if (count > 1000000000)return -1;return count;}

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Charlie Chen (陳慶裕)
Charlie Chen (陳慶裕)

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